George just bought a new scooter for $8000. he plans on keeping it until it is worth a fourth of it's original price.
he believes that every year the scooter loses an eighth of its value. he can represent the value of the scooter by the equation v = 8000(7/8)t, where v is the value of the scooter and t is the number of years that have passed.
as he was leaving the dealership he was told that the scooter really loses a sixth of it's value every year. what should george change in the equation v = 8000(7/8)t to represent this new situation?
a) replace the 7/8 with a 6.
b) replace the 8000 with 5/6.
c) switch the v and t
d) replace the 7/8 with a 5/6.

D) Replace the 7/8 with a 5/6.

Step-by-step explanation:

Given,

The original value of the scooter = $ 8000,

If it loses an eighth of its value.

Then the decrement in the price of scooter = of the original price of the scooter

Now, the final price of the scooter = Original price of the scooter - Decrement in price

Similarly, If it loses an sixth of its value.

Then, decrement in price = of 8000

And, the final price of the scooter =

Hence, Option D is correct.

d

gimmee one of those gold crowns!

~coco

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)