for the system shown below what are the coordinates of the solution that lies in quadrant ii? write your answer in form (a, b) without using spaces.
x^2+4y^2=100
4y-x^2=-20

(-6,4)

Step-by-step explanation:

The equations are:

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

Now we can solve for y:

So plugging in y = 4 into an equation and solving for x, we have:

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.