(ƒ + g)(x) = 11x2 – x + 4
Mathematics, 21.11.2019 06:31 tamera62
Find (ƒ + g)(x) where ƒ(x) = 5x2 + 4, g(x) = 6x2 – x.
(ƒ + g)(x) = 11x2 – x + 4
(ƒ + g)(x) = 11x2 – 4x
Answers: 1
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Find (ƒ + g)(x) where ƒ(x) = 5x2 + 4, g(x) = 6x2 – x.
(ƒ + g)(x) = 11x2 – x + 4
(ƒ + g)(x) = 11x2 – x + 4
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