Three consecutive numbers have a sum of 18. what are the numbers?

4,6,8

Step-by-step explanation:

First even number is x

second even number is x+2

third even number is x+4

so,equation is

x+(x+2)+(x+4)=18

3x+6=18

3x=18-6

3x=12

x=12/3

x=4

first number=4

second number=(x+2)=4+2=6

third even number=(x+4)=4+4=8

checking the answer= 4+6+8=18

answer is proved

5+6+7 because those are in order and it =18!

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

i dont understand the question? ?

step-by-step explanation: