Which statements describe the solutions to √x-2 -4=x-6 ? check all that apply. there are no true solutions to the radical equation. x = 2 is an extraneous solution. x = 3 is a true solution. there is only 1 true solution to the equation. the zeros of 0 = x2 – 5x + 6 are possible solutions to the radical equation.

Solution

Put, x=2 and x=3 in original equation

⇒For, x=2

LHS

RHS

4-6

= -2

LHS=RHS

Hence, x=2 , is solution of the system.

⇒For , x=3

.LHS=

RHS

3-6=-3

Hence, x=3 , is solution of the system.

Option C

x=3, is true solution.

Option E:

The zeros of 0 = x2 – 5x + 6 are possible solutions to the radical equation.

the answer is a

step-by-step explanation:

because your just changing the position of where the shape is

8y^50

step-by-step explanation: