Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card. what is the probability that he pulls out a 3 first and then pulls out a 2 without replacing them?

3/28

Step-by-step explanation:

Given in the question that,

stack of cards have numbers (1, 1, 2, 2, 3, 3, 3, 4)

Total number of cards = 8

Number of card with 3 on them = 3

Number of card with 2 on them = 2

To find the probability that he pulls out a 3 first and then pulls out a 2, we will multiple the probability of having 3 with 2.

Probability of having 3 = 3/8

Probability of having 2 = 2/7 (without replacing)

3/8 x 2/7 = 3/28

Thus, the answer is 3/28

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;