Arectangle's length is three more than two times its width if the perimeter of a rectangle is 66 ft what is the measurement of the length

The measure of the length is

Step-by-step explanation:

Let

x-----> the length of rectangle

y-----> the width of rectangle

we know that

The perimeter of rectangle is equal to

so

Simplify

-----> equation A

----> equation B

Substitute equation B in equation A and solve for y

Find the value of x

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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