find the x-intercepts for the parabola defined by the equation below.

y = 2x2 + 2x - 4

a.

(-4, 0) and (2, 0)

b.

(-2, 0) and (1, 0)

c.

(0, -2) and (0, 1)

d.

(0, -4) and (0, 2)

B. (-2, 0) and (1, 0)

Step-by-step explanation:

The equation can be factored as ...

y = 2(x^2 +x -2) = 2(x +2)(x -1)

The x-intercepts are the values of x where y=0, so will be the values of x that make one or the other of the binomial factors zero:

x = -2

x = 1

Then the intercept points are (-2, 0) and (1, 0). . . . . . . . . matches choice B

b

step-by-step explanation:

b

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x