Is (x-2) a factor of p(x) = x^3+2x^2-6x-4

Yes.

Step-by-step explanation:

By using Bezout's Theorem regarding polynomials, we can determine if 'x - 2' is a factor of the original P(x). The theorem states that if any polynomial P(X) is divided by x - a, where a - a real number. Then the remainder of the devision is precisely P(a). And if the remainder is 0, then that means x - a, or x - 2 in our case, is a factor of the riginal P(x).

P(2) =

Therefore x - 2 is a factor of P(x)

x=0

step-by-step explanation: