At a game show, there are 8 people (including you and your friend) in the front row. the host randomly chooses 3 people from the front row to be contestants. the order in which they are chosen does not matter. how many ways can you and your friend both be chosen?

A. C(3,8) = 56

Step-by-step explanation:

Since the order doesn't matter, it's a combination, not a permutation (answer C).

To calculate the possible combinations, we use the following formula:

In this case we have n = 8 (entire population), and r = 3 (number of chosen people)

And you have 56 in your possible answers... so answer A.

The answer is actually 6.

Step-by-step explanation:

Just took the quiz on APEX :)

215.92 dollars is the answer

hiking down a winding trail.

step-by-step explanation: