Identify the recursive formula for the following sequence:

1/2, 1 1/2, 3 1/2, 7 1/

C

Step-by-step explanation:

The problem is where does n start?

a1 = 1/2

a2 = 2*(a1) + 1/2

a2 = 2*(1/2) + 1/2

a2 = 1 + 1/2

a2 = 1 1/2

a3 = 2*a2 + 1/2

a3 = 2*(1 1/2) + 1/2

a3 = 3 + 1/2

a3 = 3 1/2

a4 = 2(3 1/2) + 1/2

a4 = 7 + 1/2

a4 = 7 1/2

an = 2*a_(n-1) + 1/2

The answer is C

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

the ordered pairs for the given function are of the form