The number of instructions n performed per second by a computer varies directly as the speed s of the computer's internal processor. a processor with a speed of 20 megahertz can perform 1 comma 600 comma 000 instructions per second.

a) find an equation of variation.

b) how many instructions per second will the same processor perform if it is running at a speed of 180 megahertz?

a)

The equation of variation is;

N = 80000*S

b)

14400000

Step-by-step explanation:

We are informed that the number of instructions N performed per second by a computer varies directly as the speed S of the computer's internal processor. This means that N and S are directly proportional;

N∝S

Introducing a constant of proportionality, k;

N=k*S

We shall find the value of k by using the information given;

N = 1600000

S = 20

k = 1600000/20

  = 80000

a)

The equation of variation is thus;

N = 80000*S

b)

We are required to find N when S = 180

Using the equation of variation obtained above;

N = 80000 (180)

   = 14400000

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

step-by-step explanation: