The set of ordered pairs shown represents a function f. {(-5, 3), (4, 9), (3, -2), (0, 6)} which three ordered pairs could be added to the set so that f remains a function? a. (-3, -2), (4, 0), and (0, -1) b) (1, 6), (2, 3), and (-5, 9) c) (4, 0), (0, -1), and (-5, 9) d) (-3, -2), (1, 6), and (2, 3)

d.(-3,-2),(1,6) and (2,3)

Step-by-step explanation:

We are given that the set of ordered pairs shown represents a function f

{(-5,3),(4,9),(3,-2),(0,6)}

We have to find that which three ordered pairs could be added to the set so that function remains same.

Function: It is mapping between  elements of two sets A and B and every element of set A is uniquely mapped with each element of set B.

Or We can say that there is only one image of each element .

In the function

Image of -5 is 3 ,image of 4 is 9 ,image of 3 is -2 and image of 0 is 6.

a.(-3,-2),(4,0),(0,-1)

There is image of 0 is -1

It is not possible because two images of one element is not possible.

Hence, option a is false.

b.(1,6),(2,3) and (-5,9)

There is image of -5 is 9

Image of -5 is 3 in given function

Two  images one elements is not possible .Hence, option b is false.

c.(4,0),(0,-1) and (-5,9)

It is false because image of 4 is 0 and image of -5 is 9 which is not possible.

Hence, option C is false.

d.(-3,-2),(1,6) and (2,3)

Image of -3 is -2

Image of 1 is 6

Image of 2 is 3

It is true because every element have different image and function remain same.

Therefore, option D is true.

idk

step-by-step explanation:

answer: idk

step-by-step explanation: