Acontainer contains 10 diesel engines. the company chooses 8 engines at random, and will not ship the container if any of the engines chosen are defective. find the probability that a container will be shipped even though it contains 2 defectives if the sample size is 8.

16/25

Step-by-step explanation:

We just have to find the probability that the 8 non-defects are chosen.

1. Chance first defect is undetected: 8/10 = 4/5

2. Chance second defect is undetected: 4/5

3. Total probability': 4/5 * 4/5 = 16/25

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation: