Solve |3x - 4| = 15
a) {-19/3, 19/3}
b) {11/3, 19/3}
c) {-11/3, 19/3}

option C

{-11/3 , 19/3}

Step-by-step explanation:

Given in the question an equation

|3x-4| = 15

To solve the absolute equation we need to add ± on right side of equation.

3x-4 = ±15

3x = 15+4 or 3x = -15 + 4

3x = 19  or  3x = -11

x = 19/3  or  x = -11/3

The solution of |3x-4| = 15 is {-11/3 , 19/3}

The solution of I3x - 4I = 15 is {-11/3 , 19/3}

Step-by-step explanation:

* Lets explain the meaning of I I (absolute value)

- The absolute value of any number is the magnitude of the number

means the value of the number without its sign, we ignore the sign

of the number

- The absolute never equal a negative value

- If IxI = a, then x = a or x = -a

* Now lets solve the problem

∵ I3x - 4I = 15

∴ 3x - 4 = 15 OR 3x - 4 = -15

* Lets solve the two equation

∵ 3x - 4 = 15 ⇒ add 4 to both sides

∴ 3x = 19 ⇒ divide both sides by 3

∴ x = 19/3

∵ 3x - 4 = -15 ⇒ add 4 to both sides

∴ 3x = -11 ⇒ divide each side by 3

∴ x = -11/3

* The solution of I3x - 4I = 15 is {-11/3 , 19/3}

1.5%

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !