Which of the following is not an equation of a simple, even polynomial function? y = | x | y = x2 y = x3 y = -x2

Step-by-step explanation:

The absolute value function prevents the expression from being a polynomial. The degree of 3 in y^3 is an odd number so that polynomial function will not be even.

The equation is not an equation of a simple , even polynomial function.

Step-by-step explanation:

Even  function : A function  is even when its graph is symmetric with respect to y-axis.

Algebrically , the function f is even if and only if

f(-x)=f(x) for all x in the domain of f.

When the function does not satisfied the above condition then the function is called non even function.

f(x) f(-x)

Now , we check given function is even or not

A. y=

If x is replaced by -x

Then we get the function

f(-x)=

f(-x)=

Hence, f(-x)=f(x)

Therefore , it is even  polynomial function.

B.

If x is replace by -x

Then we get

f(-x)=

f(-x)=

Hence, f(-x)=f(x)

Therefore, it is even polynomial function.

C.

If x is replace by -x

Then we get

f(-x)=

f(-x)=

Hence, f(-x) f(x)

Therefore, it is not even polynomial function.

D.

If x is replace by -x

Then we get

f(-x)= -

f(-x)=-

Hence, f(-x)=f(x)

Therefore, it is even polynomial function.

C. is not simple , even polynomial function.

sorry but i cant draw that