1. in a game, if you roll a 6 on a 6-sided number cube, you lose a turn. (a) what is the probability that you roll a 6? explain your reasoning. (b) what is the probability that you don’t roll a 6? explain your reasoning. (c) what is the probability that you either roll a 6 or do not roll a 6? explain your reasoning. (d) suppose you rolled the 6-sided number cube 120 times, how many times would you expect to roll a 6? explain and show all of your work.

Try this options:

a. total - 6 digits, '6' - 1 digit, then probability of rolling a '6' is 1/6;

b. total - 6 digits, '6' - 1 digit, then probability of rolling 1,2,3,4,5 is 5/6;

c. if probability of rolling a '6' is p and not rolling a '6' is q, then p+q=1;

d. if expected probability of one rolling a '6' is 1/6, then numbers of times of rolling a '6' during 120 times is 120/6=20 times.

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step-by-step explanation:

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see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -