Acar travels along a straight road for 30 seconds starting at time t = 0. its acceleration in ft/sec^2 is given by the linear graph below for the time interval [0, 30]. at t = 0, the velocity of the car is 0 and its position is 10. what is the velocity of the car when t = 6? you must show your work and include units in your answer.

  42 ft/s

Step-by-step explanation:

The change in velocity is given by the area under the curve from t=0 to t=6. The average acceleration over that period is (10+4)/2 = 7 ft/s^2, so the change in velocity is ...

  (7 ft/s^2)(6 s) = 42 ft/s

The velocity of the car at t=6 is 42 ft/s.

the answer is true.

step-by-step explanation:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.