If (x-2) is a factor of x^3 + bx^2 - 4 , what is the value of b?

b= -1

Step-by-step explanation:

Step 1: Find out value of x

x-2 = 0

x= 2

Step 2: Substitute value of x in the equation

x^3 + bx^2-  4 = 0

(2)^3 + b (2)^2 - 4 = 0

8 + 4b - 4=0

4 - 4b = 0

4b = -4

b = -1

δabc ≅ δdcb by sas because

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bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

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