Point p is located at (x, y). the point is reflected in the y-axis. point p’s image is located at

-x,y?

Step-by-step explanation:

if it's being reflected across the y-axis then that should go in to the negative side of the graph and the same if its being reflected across the x-axis, in which case it would be x,-y

P'(-x,y)

Step-by-step explanation:

The question is asking you to reflect over the y-axis. You pick a random point in the first quadrant and reflect that point over the y-axis. The point will land in the second quadrant and the x-value will have been negated (changed sign).

Ex.

(5,4) would become (-5,4)

P(x,y) reflected over the y-axis P'(-x,y)

grab rope, tie a loop-de-loop, put it around ur neck, now jump while its tied to a high place. now your shoes are cool.

step-by-step explanation:

ghjmutmum

step-by-step explanation: