If f(x)= x-3/x , g(x)=x+3 , and h(x)=2x+1 , what is (g*h*f)(x) ?

a: 3x-6/x

b: 6x-6/x

c: 2x+4/2x+7

d: 4x-3/x

Option B is correct

Step-by-step explanation:

We need to find g(h(f(x))

We first find h(f(x))

f(x) = x-3/x

Putting value of f(x) in place of x in h(x)

h(x) = 2x+1

h(f(x)) = 2(x-3/x) + 1

         = 2(x-3/x) + 1

         = 2x -6 /x +1

         = 2x-6 +x/x

         = 3x-6/x

Now, putting value of h(f(x)) in g(x)

g(x) = x+3

g(h(f(x)))= (3x-6/x) + 3

            = 3x-6/x + 3

            = 3x-6+3x/x

            = 6x-6/x  

So, Option B is correct.

a box 3 3/4 feet long or 4+ feet.

step-by-step explanation:

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse