How much glass id needed to manufacture 1000 paperweights? explain your reasoning.

1000. V=1/3 (h) (a^2)

V= 4(9)(1/3)

V=12

12(1000)=12000

The amount of glass needed to make 1000 paperweights would be 1200 inches cubed

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

50

step-by-step explanation: