Acertain tennis player makes a successful first serve 70% of the time. assume that each serve is independent of the others. if she
serves 6 times, what's the probability that she
all 6 serves in?
exactly 4 serves in?
at least 4 serves in?
no more than 4 serves in?

this is a binomial problem: p = 0.7 and q = 0.3

a) (0.7)^6

b) (6C4)(0.7)^4(0.3)^2

c) Pr ( at least 4) = Pr(4) + Pr(5) + Pr(6) = (6C5)(0.7)^5(0.3) + (0.7)^6

d) Pr (no more than 4) = 1 - Pr(at least 4) = 1 - (answer from c)

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

pls mark as brainliest

the correct answers i think are b. and d.

give me brainliest if it is correct!