Michael is organizing 5,272 blocks into bins at the toy store. he needs to put the same number of blocks in each bin without any leftover blocks. how many bins could michael use for the blocks? a) 3. b) 4. c) 5. d) 9.

B) 4 bins

Step-by-step explanation:

The criteria of divisibility are rules that serve to know if a number is divisible by another without having to perform the division.

A number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).

5,272

5 + 2 + 7 + 2 = 16

1 + 6 = 7 →This number isn't divisible by 3, therefore 5,272 isn't divisible by 3

Divisibility by 5 is easily determined by checking the last digit in the number , and seeing if it is either 0 or 5. If the last number is either 0 or 5, the entire number is divisible by 5.

5,272 → the last digit is 2; isn't 0 or 5, therefore 5,272 isn't divisible by 5.

The basic rule for divisibility by 4 is that if the number formed by the last two digits in a number is divisible by 4, the original number is divisible by 4

5,272

the last two digits are 72, and 72/4 = 18

72 is divisible by 4, therefore 5,272 is divisible by 4

Since 5,272 is divisible by 4, Michael can use 4 bins to organize the blocks, and he needs to put 5,272/4 = 1,318 blocks in each bin.

B) 4 bins

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

answer: r there any options?

step-by-step explanation: