Adiameter of a circle has endpoints p(-10,-2) and q(4,6)
a find the center of the circle.
b. find the radius radical form
c. write an equation for the circle

  a) center: (-3, 2)

  b) radius: √65

  c) equation: (x +3)² +(y -2)² = 65

Step-by-step explanation:

a) The center (point A) is the midpoint of the diameter, so its coordinates are the average of the endpoint coordinates:

  A = (P +Q)/2 = ((-10, -2) +(4, 6))/2

  = (-10+4, -2+6)/2 = (-6, 4)/2

  A = (-3, 2)

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b) The radius is the distance from the center to one end of the diameter. The distance formula can be used to find that.

  r = √((x2 -x1)² +(y2 -y1)²) = √((4-(-3))² +(6 -2)²) = √(49+16)

  r = √65

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c) The circle centered at (h, k) with radius r has formula ...

  (x -h)² +(y -k)² = r²

So the formula for this circle is ...

  (x +3)² +(y -2)² = 65

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step-by-step explanation:

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