D=vt-(1/2)at^2 to find a. in the formula, d is displacement, v is final velocity, a is acceleration, and t is time

  a = 2(vt -d)/t^2

Step-by-step explanation:

Add the term containing "a":

  d + a(t^2/2) = vt

Subtract d:

  a(t^2/2) = vt -d

Multiply by the inverse of the coefficient of "a":

  a = 2(vt -d)/t^2

b. astronomers

a: inscribed angles

step-by-step explanation:

i reviewed this question with a peer and teacher, seems to be correct, me later