Asubmarine is at a depth of 2 1/3 km below sea level and if it starts ascending at the rate of 800m/h. then find its position after 2 hours?

66 ⅔ m

Step-by-step explanation:

2 ⅓ km can be written in improper form as 5/3 km.

There's 1000 m in 1 km, so we can convert this:

5/3 km × (1000 m / km) = 5000/3 m

The submarine rises at 800 m/h.  So after 2 hours:

distance = rate × time

d = 800 m/h × 2 h

d = 1600 m

So the new position is:

5000/3 m − 1600 m

5000/3 m − 4800/3 m

200/3 m

66 ⅔ m

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

168

step-by-step explanation:

i am pretty sure that the answer is 168