Janelle invested $13000 into two mutual funds. fund a earned 6% profit during the first year, well fund b suffered a 3.5% loss. if she received a total of 324$ profit, how much had she invested in each mutual fund?

amount invested in mutual fund B; $4,800

amount invested in mutual fund A; $8,200

Step-by-step explanation:

Let the amount invested in mutual fund B be x. Then the amount invested in fund A would be;

(13000-x)

The loss emanating from fund B would be;

3.5% of x

=(3.5/100)*x

=0.035x

The profit resulting from investment in fund A would be;

6% of (13000-x)

= (6/100)*(13000-x)

=0.06(13000-x)

=780-0.06x

The total profit earned from funds A and B in terms of x will be;

780 - 0.06x + (-0.035x)

=780 - 0.095x

The total profit earned was 324, thus;

780 - 0.095x = 324

solving for x;

780 - 324 = 0.095x

456 = 0.095x

x = 4800

Then the amount invested in fund A would be;

13000 - 4800 = 8200

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x