Write the equation of a line that is perpendicular to the given line and that passes through the given point.
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y = (-3/2)x - 4

Step-by-step explanation:

If y = (2/3)x + 9, the slope is 2/3.  Any line perpendicular to this line would have the slope -3/2, which is the negative reciprocal of 2/3.

If the perpendicular line passes thru (-6, 5), then the equation in slope-intercept form would be:

y = mx + b, or (here) 5 = (-3/2)(-6) + b.  From this we see that b = -4, and the desired equation is y = (-3/2)x - 4 (Answer Choice #3)

the two may have that, even a breakdown is probably offered

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is