Solve the equation for the interval

x=0,3π/2,π

Step-by-step explanation:

Given

sin^2  x+sin⁡x=0

sin x is a common factor

so,

sin⁡x (sin⁡x+1)=0

We can put both factors one by one equal to zero

sin⁡x=0

x=  sin^(-1)⁡0

sin⁡x  is zero at 0 and π

x=0,π

sin⁡x+1=0

sin⁡x= -1

x=  sin^(-1)⁡(-1)

sin is -1 for 3π/2

So,

x=3π/2

So,

x=0,3π/2,π

answer:

your answer is: c. 196 7/8 in^3.

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb