John ran the 100-m dash with a time of 9.87sec. if this pace could be maintained for an entire 26-mi marathon, what would his time be? (notice that 1 m ≈ 3.281 ft and 1 mi = 5280 ft.)

1 hour

8 min

49 sec

Step-by-step explanation:

we know that

1 m=3.281 ft

1 mi=5,280 ft

Convert 26 mi to ft

26 mi=26*5,280=137,280 ft

Convert 137,280 ft to m

137,280 ft=137,280/3.281=41,840.90 m

using proportion

9.87/100=x/41,840.90

x=41,840.90*(9.87)/100

x=4,129.70 sec

Remember that

1 hour=3,600 sec

1 hour=60 min

1 min=60 sec

4,129.70 sec=4,129.70/3,600= 1.147 h

0.147*60=8.82 min

0.82*60=49 sec

therefore

1 hour

8 min

49 sec

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

he answer is x=1x3 because x=1 to x=3