Katie is going to rent an apartment and has to choose the number of bedrooms the apartment has, the type of parking she will use, and the length of the lease that she will sign. she has three options for the number of bedrooms (one, two, or three bedrooms), three options for the type of parking (street, assigned, or garage spots), and four options for the length of the lease (1, 6, 12, or 24 months.) how many possible combinations are there for the number of bedrooms, parking options, and the length of the lease that katie could select?

how many possible combinations are there for the number of bedrooms, parking options, and the length of the lease that katie could select?

72
36
27
48
10

  36

Step-by-step explanation:

The total number of options is the product of the numbers of independent options: 3×3×4 = 36.

__

For each of the bedroom options, she can choose any parking option, so can have ...

  1 br, street parking

  2 br, street parking

  3 br, street parking

  1 br, assigned parking

  2 br, assigned parking

  3 br, assigned parking

  1 br, garage spots

  2 br, garage spots

  3 br, garage spots

That is, 3×3 = 9 options. Any of these can be put with any of the four lease options, for a total of 9×4 = 36 options altogether.

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

i think the answer is b