Which system of linear inequalities is shown in the graph?
a)
y < x + 4
y ≥ -3x - 2
b)
y < x + 4
y ≤ -3x - 2
c)
y > x + 4
y ≤ -3x - 2
d)
y > x + 4
y ≥ -3x - 2
any would be greatly appreciated, !

D)

y > x + 4

y ≥ -3x - 2

Step-by-step explanation:

Blue line's boundary is above the line and dotted (>) so the equation: y > x + 4

Red line's boundary is above the line and solid (≥) so the equation: y ≥ -3x - 2

Answer

D)

y > x + 4

y ≥ -3x - 2

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

d i think

step-by-step explanation: