If f(x) = -x - 2 and g(x) = x2, what is (gº)?

16

Step-by-step explanation:

(gºf)(x) involves using function f as the input to function g and is called a "composition."

g(x) = x^2, so if we use f(x) = -x -2 as input, we get

(gºf)(x) = (-x -2)^2.

At x = -6, we have:

(gºf)(-6) = (-[-6] -2)^2  =  4^2    =16

it has the same slope and a different y-intercept

hope this : )