Baseball player hits a ball on an angle of 54° and a height of 4 1/2 feet if the balls initial velocity after being is 152 ft./s if no one catches the ball when will hit the ground

The answer is:

The ball will hit the ground in 7.69 seconds.

To solve this problem, we need to apply the following projectile motion equation:

To calculate when the ball wil hit the ground, in other words the time of flight, we need to make "y" equal to 0, and considerate the initial height, so, we have:

Then, we are given the following information:

Now, substituting and solving, we have:

We have a quadratic equation, where:

Now, using the quadratic equation to find the values of "t" , we have:

Substituting we have:

Therefore, since the time cannot be negative, we have to discard "t1", so, the answer is: 7.69 seconds

Hence, the ball will hit the ground in 7.69 seconds.

Have a nice day!

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

-1/2 +2

step-by-step explanation: