Abag contains 10 marbles: 4 are green, 4 are red, and 2 are blue. dale chooses a marble random, and without putting it back, chooses another one at random. what is the probability that the first marble is blue and the second one is green?

for blue its 1/5 or 2/10 while for its 4/9 for green

Step-by-step explanation: since the bag is full you have all 10 marbles. if you put 10 to the 2 that you have it would leave you with 2/10. now simplify that by dividing it by a number that goes into both. in this case both can be divided by 2 so that leaves 2/2 which is 1 and 10/2 which is 5. 1/5 would be the fraction. now you have 9 marbles after you take one and there are 4 green marbles. since there is no number that can divide into both 4 and 9 evenly we just put it as 4/9 having your answer

idk

step-by-step explanation:

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this