Ma 912. g.1.4
60. what is the slope of a line that passes through the point (-1, 1) and is parallel to a line that passes through
(3.6) and (1, -2)?

Step-by-step explanation:

Going from (1, -2) to (3,6), x increases by 2 and y increases by 8.  Thus, the slope m of this line is m = rise / run = 8/2 = 4.

I think you meant, "What is the EQUATION of the line that passes through the point (-1, 1) and is parallel to a line that passes through

(3, 6) and (1, -2)?  We have seen that this slope is -4.  

Starting with the point-slope equation of a line, we have:

y - 6 = -4(x - 3)

is this a dating site too?

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west