Part a: factor x2a2 + 3xa2 + 2a2. show your work. (4 points)

I am not sure of the equation but I interpreted it as x^2a^2+3xa^2+2a^2

Step-by-step explanation:

X^2a^2+3xa^2+2a^2

1. a^2 (x^2+3x+2)

2.a^2(x^2+2x+x+2)

3. a^2(x(x+2)+x+2)

4. a^2(x+2)(x+1)

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl