The limit of sqrt(9x^4 + 1)/(x^2 - 3x + 5) as x approaches infinity is

(a) 1

(b) 3

(c) 9

(d) nonexistent

B. 3.

Step-by-step explanation:

At the limit we can take the numerator  to be √(9x^4) = 3x^2

The function is of the form ∞/ ∞ as x approaches ∞ so we can apply l'hopitals rule:

Differentiating top and bottom we have   6x / 2x - 3. Differentiating again we get 6 / 2 = 3.

Our limit as x  approaches infinity  is 3.

the answer is b