There are two spinners. the first spinner has three equal sectors labeled 1, 2, and 3. the second spinner has four equal sectors labeled 3, 4, 5, and 6. spinners are spun once. how many outcomes do not show an even number on the first spinner and show a 6 on the second spinner?

2 outcomes

Step-by-step explanation:

Let's list count all the possible outcomes:

(1,3) (1,4) (1,5) (1,6)

(2,3) (2,4) (2,5) (2,6)

(3,3) (3,4) (3,5) (3,6)

As expected, there are 12 (3x4) possible outcomes.

How many outcomes do not show an even number (so showing 1 or 3) on the first spinner and show a 6 on the second spinner?

There are two cases where 6 is on the second spinner and NOT an even number on the first spinner: (1,6) and (3,6)

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4