Find the equation in standard form of the line parallel to y=-1/5x+7 and passing through the point (-10,-3)

the desired equation is y = (-1/5)x - 5.

Step-by-step explanation:

Parallel lines have the same slope.  Here that slope is -1/5.

Let's use the slope-intercept form of the equation of a straight line:

y = mx + b

We know this new line passes through (-10, -3).  Substitute -3 for y in y = mx + b, as well as -10 for x and -1/5 for m:

-3 = (-1/5)(-10) + b and solve for b:

-3 = 2 + b.  Then b = -5, and the desired equation is y = (-1/5)x - 5.

the circle one

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°