Urgent ! 1a company creates tin boxes out of sheet metal. what measure should it use to find out how much sheet metal it needs to make a box that is 6 cm by 4 cm by 18 cm?
surface area
volume
area
lateral area

  surface area

Step-by-step explanation:

The "surface area" of a figure refers to the total external area, the sum of areas of all of the sides and ends. Since sheet metal must cover all of these places, the notion of "surface area" would seem to apply.

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"Volume" has to do with how much space is filled. It would pertain if the company were making solid tin ingots of the dimensions given.

"Area" and "lateral area" generally have to do with portions of the area of the box. "Area" can be interpreted in different ways, depending on context, but may be considered to refer to the area of one face of the box. "Lateral area" would refer to the total area of the sides of the box, excluding the ends. For a rectangular box, "sides" and "ends" would need further description.

answer. d.289 hope that

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)