Find the missing factor. 5y2 + 4y - 1 = (5y - 1)( )

(y + 1)

Step-by-step explanation:

Given

5y² + 4y - 1

To factorise the quadratic

Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term

product = 5 × - 1 = - 5 and sum = + 4

The factors are + 5 and - 1

Use the factors to split the y- term

5y² + 5y - y - 1 ( factor the first/second and third/fourth terms )

= 5y(y + 1) - 1(y + 1) ← factor out (y + 1) from each term

= (y + 1)(5y - 1)

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

these sign is used to tell weather the number is greater or less than the number   <   or >     but this sign means its equal =    

hope this you and

step-by-step explanation: