What is the constant term of -3x^4-7x+2

The equation written in the standard form is written as

ax^4 + bx+c

where a and b are the coefficients of the second-order and first-order term, while c is the constant term.

The equation we have in this problem is

By comparing (1) with (2), we immediately see that

A = -3x^4

B = 7x

C = 2

Step-by-step explanation:

Hope this helps :)

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47