Match each quadratic equation with its solution set. 2x2 − 32 = 0 4x2 − 100 = 0 x2 − 55 = 9 x2 − 140 = -19 2x2 − 18 = 0 {-8, 8} arrowright {-4, 4} arrowright {-5, 5} arrowright {-11, 11} arrowright

For this case we solve each of the equations:

Adding 32 to both sides of the equation:

Dividing between 2 on both sides of the equation:

Applying square root to eliminate the exponent:

Second equation:

Adding 100 to both sides of the equation:

Dividing between 4 on both sides of the equation:

Applying square root to eliminate the exponent:

Third equation:

Adding 55 to both sides of the equation:

Applying square root to eliminate the exponent:

Fourth equation:

Adding 140 to both sides of the equation:

Applying square root to eliminate the exponent:

Fifth equation:

Adding 18 to both sides of the equation:

2x ^ 2 = 18

Dividing between 2 on both sides of the equation:

Applying square root to eliminate the exponent:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3