Will give brainliest answer. simplify and select the answer with the appropriate restrictions for the variable.

Question 4:

(x² - 25) / (x - 5)

= (x² - 5²) / (x - 5)

= [(x - 5) · (x + 5)] / (x - 5)

= x + 5

The denominator can't be equal to 0, therefore:

x - 5 ≠ 0 ⇔ x ≠ 5

Question 5:

(3x² - 6x) / (x² - 2x - 8)

= [3x (x - 2)] / (x² + 4x - 2x - 8)

= [3x (x - 2)] / [x (x + 4) - 2 (x + 4)]

= [3x (x - 2)] / [(x - 2) (x + 4)]

= 3x / (x + 4)

The denominator can't equal to 0, therefore:

x + 4 ≠ 0 ⇔ x ≠ -4

2 is the final ! : )