What is the factorization of 216x12 - 64? o (6x3 – 4)(36x6 + 24x3 + 16) (6x3 – 4)(36x9 + 24x3 + 16) (6x4 – 4)(36x8 + 24x4 + 16) (6x4 – 4)(36x12 + 24x4 + 16)

( 6x^4 -4)((36x^8) +24x^4  +16)

Step-by-step explanation:

216x^12 - 64

This is the difference of cubes

a^3 – b^3 = (a−b)(a^2+ab+b^2)

where a = 6x^4   and b = 4

(216x^12 - 64) = ( 6x^4 -4)((6x^4)^2 +6x^4 * 4 +4^2)

                      = ( 6x^4 -4)((36x^8) +24x^4  +16)

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: