Yesterday morning at 8 a. m. the temperature was -14˚f. at noon it was 10 degrees warmer. the temperature increase between noon and and 4 p. m. was twice the temperature increase between 8 a. m. and noon. what was the temperature at 4 p. m?me quick.

think the answer is 30 degrees. if not than it is 20 degrees. not 100% sure. let me know if it was right.

gill russ

{3 + i, 3 - i, 3, -1}

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2