Determine whether the ratio test is inconclusive (that is, it fails to give a definite answer), conclusive (convergent), or conclusive (divergent) for each series. (a) ∞ 1 n3 n = 2 inconclusive conclusive (convergent) conclusive (divergent) (b) ∞ n 3n n = 3 inconclusive conclusive (convergent) conclusive (divergent) (c) ∞ (−6)n − 1 n n = 2 inconclusive conclusive (convergent) conclusive (divergent) (d) ∞ 5 n 1 + n2 n = 3 inconclusive conclusive (convergent) conclusive (divergent)

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

i got 10.28 but that rounds up to 10.3

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: