Aset of telephone poles is stacked in a pile, 8 layers high. the top layer consists of 20 telephone poles. the next layer down consists of 24 telephone poles. the third layer consists of 28 telephone poles. if this pattern continues for the remaining 5 layers, how many telephone poles are in the pile? a. 224 b. 244 c. 252 d. 272

D. 272 poles

Explanation:

We are given that:

The top layer has 20 poles, the next down one has 24 poles and the third one has 28 poles

We can note that each layer has 4 poles more that the one above it

Based on this, we can get the number of poles in each layer as follows:

Top layer has 20 poles

Second one has 20 + 4 = 24 poles

Third one has 24 + 4 = 28 poles

Fourth one has 28 + 4 = 32 poles

Fifth one has 32 + 4 = 36 poles

Sixth one has 36 + 4 = 40 poles

Seventh one has 40 + 4 = 44 poles

Eighth one has 44 + 4 = 48 poles

Now, we can get the total number of poles by adding the poles in all layers

This is done as follows:

Total number of poles = 20 + 24 + 28 + 32 + 36 + 40 + 44 + 48

Total number of poles = 272 poles

Hope this helps :)

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet